Solve the equation
*x*^{log29} + *x*^{2}(3^{log2x}) = *x*^{log215}.

2^{log2(9y)} + 4^{y}(3^{log2(2y)}) = 2^{log2(15y)}

then
⎛⎝(3)/(5)⎞⎠^{y} + ⎛⎝(4)/(5)⎞⎠^{y} = 1.

The function from the left side is decreasing, therefore the only real solution is *y* = 2 or *x* = 1.